Updates from aaaaaaaaa on Rainbow Dash Network!
aaaaaaaaa: @haganbmj Good call. It is done.
aaaaaaaaa's status on Thursday, 23-Jun-11 20:27:30 UTC
@haganbmj Good call. It is done.
aaaaaaaaa: @rainbowflash No need to apologize. I'll think about the colours. :)
aaaaaaaaa's status on Thursday, 23-Jun-11 20:21:55 UTC
@rainbowflash No need to apologize. I'll think about the colours. :)
aaaaaaaaa: @rainbowflash Hmm... So you think it should be less monochromatic?
aaaaaaaaa's status on Thursday, 23-Jun-11 20:20:00 UTC
@rainbowflash Hmm... So you think it should be less monochromatic?
aaaaaaaaa: So, I redesigned my site the other day. Can any artist bronies offer their opinions from a design perspective? http://www.edwardkim.name
aaaaaaaaa's status on Thursday, 23-Jun-11 20:16:33 UTC
So, I redesigned my site the other day. Can any artist bronies offer their opinions from a design perspective? http://www.edwardkim.name
aaaaaaaaa: @extremedash Deter them with yarn.
aaaaaaaaa's status on Tuesday, 14-Jun-11 18:55:23 UTC
@extremedash Deter them with yarn.
aaaaaaaaa: @flaxx That sounds fantastic! Have fun.
aaaaaaaaa's status on Thursday, 09-Jun-11 12:47:35 UTC
@flaxx That sounds fantastic! Have fun.
aaaaaaaaa: @sopada Mhm, it's a very nice style. Although I think my favourite pony-mane-style is actually Octavia's.
aaaaaaaaa's status on Wednesday, 08-Jun-11 02:16:27 UTC
@sopada Mhm, it's a very nice style. Although I think my favourite pony-mane-style is actually Octavia's.
aaaaaaaaa: @sopada Fluttershy is my favourite, too. But having said that, Rainbow Dash does have all those pretty colours going for her.
aaaaaaaaa's status on Tuesday, 07-Jun-11 21:24:11 UTC
@sopada Fluttershy is my favourite, too. But having said that, Rainbow Dash does have all those pretty colours going for her.
aaaaaaaaa: @darklycute My pins came in the mail today! I immediately put them on my school/work bag. Thanks again! :) http://ur1.ca/4d4d9
aaaaaaaaa's status on Tuesday, 07-Jun-11 15:47:26 UTC
@darklycute My pins came in the mail today! I immediately put them on my school/work bag. Thanks again! :) http://ur1.ca/4d4d9
aaaaaaaaa: Won a poker game with my friends. 2 hour game with 5 people for a total of $7 in winnings. Student poker is hilarious.
aaaaaaaaa's status on Sunday, 05-Jun-11 02:57:46 UTC
Won a poker game with my friends. 2 hour game with 5 people for a total of $7 in winnings. Student poker is hilarious.
aaaaaaaaa: Mmmmm, napping while listening to the rain. Hooray for thunderstorms!
aaaaaaaaa's status on Saturday, 04-Jun-11 15:13:24 UTC
Mmmmm, napping while listening to the rain. Hooray for thunderstorms!
aaaaaaaaa: Heading out to take a look at my new house. Hooray for cheap student housing!
aaaaaaaaa's status on Friday, 03-Jun-11 21:28:23 UTC
Heading out to take a look at my new house. Hooray for cheap student housing!
aaaaaaaaa: @bigponymac That's pretty rad. I like it!
aaaaaaaaa's status on Friday, 03-Jun-11 01:56:23 UTC
@bigponymac That's pretty rad. I like it!
aaaaaaaaa: For science, I have spent the last hour of my life creating this. http://ur1.ca/4bz5l
aaaaaaaaa's status on Friday, 03-Jun-11 01:05:24 UTC
For science, I have spent the last hour of my life creating this. http://ur1.ca/4bz5l
aaaaaaaaa: @edman Actually, I should correct myself: If you only want the acceleration in g forces, then it's actually quite trivial, since you would ignore the acceleration due to gravity.
aaaaaaaaa's status on Friday, 03-Jun-11 00:30:42 UTC
@edman Actually, I should correct myself: If you only want the acceleration in g forces, then it's actually quite trivial, since you would ignore the acceleration due to gravity.
aaaaaaaaa: @starlightbolt I don't know if it's a two-step process. I would use a = v^2/r for the centripetal acceleration. To calculate the overall acceleration at any point is somewhat involved, because the portion of gravity that contributes to the centripetal acceleration is varying as a function of theta (or as a function of time, if you prefer). However, it's not too difficult to calculate the maximum g-forces experienced (at the bottom of the arc). As it turns out, I'm actually making an infographic about this right now.
aaaaaaaaa's status on Friday, 03-Jun-11 00:29:36 UTC
@starlightbolt I don't know if it's a two-step process. I would use a = v^2/r for the centripetal acceleration. To calculate the overall acceleration at any point is somewhat involved, because the portion of gravity that contributes to the centripetal acceleration is varying as a function of theta (or as a function of time, if you prefer). However, it's not too difficult to calculate the maximum g-forces experienced (at the bottom of the arc). As it turns out, I'm actually making an infographic about this right now.
aaaaaaaaa: I just saw this: http://1.bp.blogspot.com/-uG3_RgX9JA0/TboU21S9gNI/AAAAAAAAD5w/zkR3VV91S8Y/s1600/6733226c0117931aa6df7c8d3a8e7127.jpg While it's a commendable effort, the physics is brutally wrong in it. Would it be pretentious to try to correct it?
aaaaaaaaa's status on Thursday, 02-Jun-11 23:49:43 UTC
I just saw this: http://1.bp.blogspot.com/-uG3_RgX9JA0/TboU21S9gNI/AAAAAAAAD5w/zkR3VV91S8Y/s1600/6733226c0117931aa6df7c8d3a8e7127.jpg While it's a commendable effort, the physics is brutally wrong in it. Would it be pretentious to try to correct it?
aaaaaaaaa: @elementalparadise I spent my first year in Guelph's party res. It was... an interesting experience, to say the least. I'm planning to spend the rest of my undergrad in a quieter atmosphere. Gotta get those grades and whatnot.
aaaaaaaaa's status on Thursday, 02-Jun-11 21:59:44 UTC
@elementalparadise I spent my first year in Guelph's party res. It was... an interesting experience, to say the least. I'm planning to spend the rest of my undergrad in a quieter atmosphere. Gotta get those grades and whatnot.
aaaaaaaaa: @elementalparadise uToronto, eh? Haha, yeah, it's pretty notorious for being academically focussed. I have quite a few friends there studying sciences.
aaaaaaaaa's status on Thursday, 02-Jun-11 21:31:10 UTC
@elementalparadise uToronto, eh? Haha, yeah, it's pretty notorious for being academically focussed. I have quite a few friends there studying sciences.
aaaaaaaaa: @scribus Mhm. You can't see it in the photo, but Pinkie Pie's tail is also done really well.
aaaaaaaaa's status on Thursday, 02-Jun-11 20:48:07 UTC
@scribus Mhm. You can't see it in the photo, but Pinkie Pie's tail is also done really well.
aaaaaaaaa's status on Thursday, 02-Jun-11 20:47:23 UTC
@pinkiederp Toys R Us.
aaaaaaaaa: @starshine Blame Hasbro. But whatever, once more accurate models come out, I'll buy those too.
aaaaaaaaa's status on Thursday, 02-Jun-11 20:47:10 UTC
@starshine Blame Hasbro. But whatever, once more accurate models come out, I'll buy those too.
aaaaaaaaa: Best day ever! http://ur1.ca/4bwx2
aaaaaaaaa's status on Thursday, 02-Jun-11 20:37:12 UTC
Best day ever! http://ur1.ca/4bwx2
aaaaaaaaa's status on Thursday, 02-Jun-11 01:44:15 UTC
@starshine Van Gogh?
aaaaaaaaa: @stockingsparkle Welcome! I'm sure you'll find that RDN is the friendliest of friendly places! (and the most humble)
aaaaaaaaa's status on Thursday, 02-Jun-11 01:41:41 UTC
@stockingsparkle Welcome! I'm sure you'll find that RDN is the friendliest of friendly places! (and the most humble)
aaaaaaaaa: Okay, this is officially the coolest logo I've seen in a while: http://www.equestriachronicles.com/
aaaaaaaaa's status on Wednesday, 01-Jun-11 20:33:04 UTC
Okay, this is officially the coolest logo I've seen in a while: http://www.equestriachronicles.com/
aaaaaaaaa: All that math this morning has gotten me worked up, so I imagined this fun scenario: Rainbow Dash has fallen prey to one of Pinkie Pie's diabolical pranks! Due to a paint-related mishap, her light-blue coat is now dyed green (lambda_1 = 510 nm). Not wanting to be seen in this state by you, the diligent stationary observer, she races in a straight line towards you, in an attempt to blue-shift her coat back to its original light-blue colour (lambda_2 = 480 nm). How fast must she fly in order to have you perceive her coat as its original colour? Assume Doppler shifting in flat spacetime. (For reference, the answer that I worked out is 1.8 x 10^7 m/s - much faster than the required speed for a Sonic Rainboom!).
aaaaaaaaa's status on Wednesday, 01-Jun-11 16:56:32 UTC
All that math this morning has gotten me worked up, so I imagined this fun scenario: Rainbow Dash has fallen prey to one of Pinkie Pie's diabolical pranks! Due to a paint-related mishap, her light-blue coat is now dyed green (lambda_1 = 510 nm). Not wanting to be seen in this state by you, the diligent stationary observer, she races in a straight line towards you, in an attempt to blue-shift her coat back to its original light-blue colour (lambda_2 = 480 nm). How fast must she fly in order to have you perceive her coat as its original colour? Assume Doppler shifting in flat spacetime. (For reference, the answer that I worked out is 1.8 x 10^7 m/s - much faster than the required speed for a Sonic Rainboom!).
aaaaaaaaa: @carcinopony Also, if you're interested, we can add more to this to make it cooler and more useful/applicable. Now that you've figured out how to calculate your wealth from having a part time job, what if you want to spend money too? How much is safe to spend? Let's say that by the end of two months (your summer vacation), you want to have saved $1400. How much can you spend per week during those two months, and come out with exactly $1400? We already know from the previous part that for your wealth, y = 200x + 500. For two months, x=8. So, y = 200*8 +500, which gives y = $2100. $2100 - $1400 = $700. In other words, you can afford to spend $700 throughout your two months of summer vacation. How much is that per week? $700/8 = $87.50. Therefore, using only linear equations and basic math, you've budgeted for $87.50 per week. Hooray!
aaaaaaaaa's status on Wednesday, 01-Jun-11 16:07:29 UTC
@carcinopony Also, if you're interested, we can add more to this to make it cooler and more useful/applicable. Now that you've figured out how to calculate your wealth from having a part time job, what if you want to spend money too? How much is safe to spend? Let's say that by the end of two months (your summer vacation), you want to have saved $1400. How much can you spend per week during those two months, and come out with exactly $1400? We already know from the previous part that for your wealth, y = 200x + 500. For two months, x=8. So, y = 200*8 +500, which gives y = $2100. $2100 - $1400 = $700. In other words, you can afford to spend $700 throughout your two months of summer vacation. How much is that per week? $700/8 = $87.50. Therefore, using only linear equations and basic math, you've budgeted for $87.50 per week. Hooray!
aaaaaaaaa: @carcinopony I'm sorry. I think I may have gone overboard using function notation - I think that's introduced in Grade 11 in most North American schoolboards. Let me try again: You're probably used to seeing linear equations in the "y = mx + b" form. "m" is your slope, or rate of change. In the finance example, the "rate of change" at which your wealth changes is simply your payrate, or $200 per week. The "b," is the y-intercept, or you can also think of it as an "initial value." Since you start with $500 saved, then b = 500. Thus, to determine your wealth in that example, the linear equation should be y = 200x + 500. Is that explanation clearer?
aaaaaaaaa's status on Wednesday, 01-Jun-11 16:00:45 UTC
@carcinopony I'm sorry. I think I may have gone overboard using function notation - I think that's introduced in Grade 11 in most North American schoolboards. Let me try again: You're probably used to seeing linear equations in the "y = mx + b" form. "m" is your slope, or rate of change. In the finance example, the "rate of change" at which your wealth changes is simply your payrate, or $200 per week. The "b," is the y-intercept, or you can also think of it as an "initial value." Since you start with $500 saved, then b = 500. Thus, to determine your wealth in that example, the linear equation should be y = 200x + 500. Is that explanation clearer?
aaaaaaaaa: @foxox This is true. I remember I started really learning the applications of this stuff when we did raycasting in CS class in high school. Funny story about that - In English class, we read that Victorian era people believed that light was cast from one's eyes, instead of reflected off of surfaces. i.e., Victorians believed in raycasting.
aaaaaaaaa's status on Wednesday, 01-Jun-11 15:55:56 UTC
@foxox This is true. I remember I started really learning the applications of this stuff when we did raycasting in CS class in high school. Funny story about that - In English class, we read that Victorian era people believed that light was cast from one's eyes, instead of reflected off of surfaces. i.e., Victorians believed in raycasting.
aaaaaaaaa: @carcinopony Gotcha. But even so, linear equations can be handy enough for modelling simple everyday stuff. Example: Let's say you have $500 saved up, and you also have a part time job that nets you $200 a week. How much money will you have in a month? Two months? Using your knowledge of linear equations, you can set your wealth to be W(x) = 500 + 200x where x is number of weeks worked, and thus calculate your wealth at any point in time (x = 4 for one month, x = 8 for two months).
aaaaaaaaa's status on Wednesday, 01-Jun-11 15:53:56 UTC
@carcinopony Gotcha. But even so, linear equations can be handy enough for modelling simple everyday stuff. Example: Let's say you have $500 saved up, and you also have a part time job that nets you $200 a week. How much money will you have in a month? Two months? Using your knowledge of linear equations, you can set your wealth to be W(x) = 500 + 200x where x is number of weeks worked, and thus calculate your wealth at any point in time (x = 4 for one month, x = 8 for two months).
aaaaaaaaa: @foxox This is very true. I guess what I was getting at was, it sounded like @carcinopony was talking about linear equations in an introductory context, i.e. hasn't been introduced to linear algebra yet. I may be wrong though.
aaaaaaaaa's status on Wednesday, 01-Jun-11 15:48:16 UTC
@foxox This is very true. I guess what I was getting at was, it sounded like @carcinopony was talking about linear equations in an introductory context, i.e. hasn't been introduced to linear algebra yet. I may be wrong though.
aaaaaaaaa: @foxox Linear algebra and linear equations are really different. Lin Alg is like.. matrices and vectors. Linear equations are 1st order polynomials.
aaaaaaaaa's status on Wednesday, 01-Jun-11 15:42:38 UTC
@foxox Linear algebra and linear equations are really different. Lin Alg is like.. matrices and vectors. Linear equations are 1st order polynomials.
aaaaaaaaa: @theawesomepony Starcraft is a really popular sci-fi RTS game.
aaaaaaaaa's status on Tuesday, 31-May-11 16:53:19 UTC
@theawesomepony Starcraft is a really popular sci-fi RTS game.
aaaaaaaaa: @miloth Morning. I've got work today. Hooray for Mondays, hahaha.
aaaaaaaaa's status on Monday, 30-May-11 13:08:20 UTC
@miloth Morning. I've got work today. Hooray for Mondays, hahaha.
aaaaaaaaa: @nvrrmbr Hm, how about a fanfic where the ponies are stranded on an island, Cast Away style?
aaaaaaaaa's status on Monday, 30-May-11 01:37:27 UTC
@nvrrmbr Hm, how about a fanfic where the ponies are stranded on an island, Cast Away style?
aaaaaaaaa: @darklycute Awesome work, brony!
aaaaaaaaa's status on Monday, 30-May-11 00:31:12 UTC
@darklycute Awesome work, brony!
aaaaaaaaa: @zarkanorf Thanks! I can't wait to walk into the office with my MLP pins on my work bag... hahaha.
aaaaaaaaa's status on Sunday, 29-May-11 23:53:35 UTC
@zarkanorf Thanks! I can't wait to walk into the office with my MLP pins on my work bag... hahaha.
aaaaaaaaa: @zarkanorf Fluttershy, Rainbow Dash and Celestia.
aaaaaaaaa's status on Sunday, 29-May-11 23:52:25 UTC
@zarkanorf Fluttershy, Rainbow Dash and Celestia.
aaaaaaaaa: @darklycute Just bought 3 pins. :D
aaaaaaaaa's status on Sunday, 29-May-11 23:50:43 UTC
@darklycute Just bought 3 pins. :D
aaaaaaaaa: @darklycute How much is shipping to Ontario, Canada?
aaaaaaaaa's status on Sunday, 29-May-11 23:46:17 UTC
@darklycute How much is shipping to Ontario, Canada?
aaaaaaaaa: @doctorwhooffanatic WE HAVE THE TECHNOLOGY.
aaaaaaaaa's status on Sunday, 29-May-11 23:05:20 UTC
@doctorwhooffanatic WE HAVE THE TECHNOLOGY.
aaaaaaaaa: @flutterguy93 Go for it. I BELIEVE!
aaaaaaaaa's status on Sunday, 29-May-11 23:03:39 UTC
@flutterguy93 Go for it. I BELIEVE!
aaaaaaaaa: @nvrrmbr Haha, no need to worry then. Also - math gets so much cooler after Algebra 2; I'm sure you'll enjoy it! :D
aaaaaaaaa's status on Sunday, 29-May-11 22:52:39 UTC
@nvrrmbr Haha, no need to worry then. Also - math gets so much cooler after Algebra 2; I'm sure you'll enjoy it! :D
aaaaaaaaa: @delc17 A winner is you! Want another problem? I think it might be more fun to do a harder problem involving the rainboom effect itself. :D
aaaaaaaaa's status on Sunday, 29-May-11 22:47:38 UTC
@delc17 A winner is you! Want another problem? I think it might be more fun to do a harder problem involving the rainboom effect itself. :D
aaaaaaaaa: @nvrrmbr It's actually not too bad. It's a single-equation problem. :)
aaaaaaaaa's status on Sunday, 29-May-11 22:46:39 UTC
@nvrrmbr It's actually not too bad. It's a single-equation problem. :)
aaaaaaaaa: @nvrrmbr Whoa, that is a SERIOUSLY cute version of Rainbow Dash. Is it a paper cutout? I can't quite tell from the image.
aaaaaaaaa's status on Sunday, 29-May-11 22:46:06 UTC
@nvrrmbr Whoa, that is a SERIOUSLY cute version of Rainbow Dash. Is it a paper cutout? I can't quite tell from the image.
aaaaaaaaa: Here's a good brain exercise for some bronies: Rainbow Dash flies horizontally at a constant speed of 10 m/s. At t = 0, she begins to flap her wings harder, giving her a constant horizontal acceleration of 8 m/s^2. After how many seconds will she reach Mach 1, producing a Sonic Rainboom? Assume Mach 1 is 330 m/s; ignore all drag effects.
aaaaaaaaa's status on Sunday, 29-May-11 22:40:36 UTC
Here's a good brain exercise for some bronies: Rainbow Dash flies horizontally at a constant speed of 10 m/s. At t = 0, she begins to flap her wings harder, giving her a constant horizontal acceleration of 8 m/s^2. After how many seconds will she reach Mach 1, producing a Sonic Rainboom? Assume Mach 1 is 330 m/s; ignore all drag effects.