{"version":"1.0","provider_name":"Rainbow Dash Network","provider_url":"http:\/\/rainbowdash.net\/","type":"link","title":"aaaaaaaaaa (aaaaaaaaa)'s status on Friday, 03-Jun-11 00:29:36 UTC","author_name":"aaaaaaaaaa (aaaaaaaaa)","author_url":"http:\/\/rainbowdash.net\/aaaaaaaaa","url":"http:\/\/rainbowdash.net\/notice\/151776","html":"@<span class=\"vcard\"><a href=\"http:\/\/rainbowdash.net\/user\/1022\" class=\"url\"><span class=\"fn nickname\">starlightbolt<\/span><\/a><\/span> I don't know if it's a two-step process. I would use a = v^2\/r for the centripetal acceleration. To calculate the overall acceleration at any point is somewhat involved, because the portion of gravity that contributes to the centripetal acceleration is varying as a function of theta (or as a function of time, if you prefer). However, it's not too difficult to calculate the maximum g-forces experienced (at the bottom of the arc). As it turns out, I'm actually making an infographic about this right now."}