<?xml version="1.0" encoding="UTF-8"?>
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 <version>1.0</version>
 <type>link</type>
 <provider_name>Rainbow Dash Network</provider_name>
 <provider_url>http://rainbowdash.net/</provider_url>
 <title>aaaaaaaaaa (aaaaaaaaa)'s status on Friday, 03-Jun-11 00:29:36 UTC</title>
 <author_name>aaaaaaaaaa (aaaaaaaaa)</author_name>
 <author_url>http://rainbowdash.net/aaaaaaaaa</author_url>
 <url>http://rainbowdash.net/notice/151776</url>
 <html>@&lt;span class=&quot;vcard&quot;&gt;&lt;a href=&quot;http://rainbowdash.net/user/1022&quot; class=&quot;url&quot;&gt;&lt;span class=&quot;fn nickname&quot;&gt;starlightbolt&lt;/span&gt;&lt;/a&gt;&lt;/span&gt; I don't know if it's a two-step process. I would use a = v^2/r for the centripetal acceleration. To calculate the overall acceleration at any point is somewhat involved, because the portion of gravity that contributes to the centripetal acceleration is varying as a function of theta (or as a function of time, if you prefer). However, it's not too difficult to calculate the maximum g-forces experienced (at the bottom of the arc). As it turns out, I'm actually making an infographic about this right now.</html>
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