{"version":"1.0","provider_name":"Rainbow Dash Network","provider_url":"http:\/\/rainbowdash.net\/","type":"link","title":"Bit Shift (bitshift)'s status on Wednesday, 29-Aug-12 12:18:19 UTC","author_name":"Bit Shift (bitshift)","author_url":"http:\/\/rainbowdash.net\/bitshift","url":"http:\/\/rainbowdash.net\/notice\/1864495","html":"@<span class=\"vcard\"><a href=\"http:\/\/rainbowdash.net\/user\/76\" class=\"url\" title=\"(&#x25E1;&#x203F;&#x25E1;&#x273F;)\"><span class=\"fn nickname\">thelastgherkin<\/span><\/a><\/span> As far as I can tell, as long as the requirement isn't to divide the remainder equally (and certainly it's not mentioned in @<span class=\"vcard\"><a href=\"http:\/\/rainbowdash.net\/user\/7517\" class=\"url\" title=\"Sindre\"><span class=\"fn nickname\">derpyshy<\/span><\/a><\/span>'s wording), any split is valid, as long as it doesn't disrupt the difference between the three with known relative amounts."}