{"version":"1.0","provider_name":"Rainbow Dash Network","provider_url":"http:\/\/rainbowdash.net\/","type":"link","title":"Pony (pony)'s status on Thursday, 16-Feb-12 05:08:01 UTC","author_name":"Pony (pony)","author_url":"http:\/\/rainbowdash.net\/pony","url":"http:\/\/rainbowdash.net\/notice\/992729","html":"@<span class=\"vcard\"><a href=\"http:\/\/rainbowdash.net\/user\/6135\" class=\"url\" title=\"Forest Rain\"><span class=\"fn nickname\">forestrain<\/span><\/a><\/span> @<span class=\"vcard\"><a href=\"http:\/\/rainbowdash.net\/user\/3828\" class=\"url\" title=\"Malcolm Chandler (&#x8A79;&#x6155;&#x4F83;)(Vinnie)(Mac)(Candle-Maker)(Butters)(Portia)\"><span class=\"fn nickname\">macpony55<\/span><\/a><\/span> I see.  So then would using 2 sets of headphones, for example, produce more volume together than one while they share the same signal or would it be equal?"}