<?xml version="1.0" encoding="UTF-8"?>
<oembed>
 <version>1.0</version>
 <type>link</type>
 <provider_name>Rainbow Dash Network</provider_name>
 <provider_url>http://rainbowdash.net/</provider_url>
 <title>Narwhal (narwhal)'s status on Thursday, 26-Feb-15 03:38:09 UTC</title>
 <author_name>Narwhal (narwhal)</author_name>
 <author_url>http://rainbowdash.net/narwhal</author_url>
 <url>http://rainbowdash.net/notice/3860697</url>
 <html>@&lt;span class=&quot;vcard&quot;&gt;&lt;a href=&quot;http://rainbowdash.net/user/2706&quot; class=&quot;url&quot; title=&quot;a weird entophile who feels attracted to purple cartoon characters&quot;&gt;&lt;span class=&quot;fn nickname mention&quot;&gt;mastermushi&lt;/span&gt;&lt;/a&gt;&lt;/span&gt; Since both triangles are right angled the primary trigonometric ratios can be applied to them. First, apply the primary cos ratio to the 59° and the 3.4m to find the length of the middle line connecting the two triangles. Second, use the primary cos ratio again with the length of the middle line and the 42° to find the length of x. It's very basic substitution when you actually work it out.</html>
</oembed>
