aaaaaaaaaa (aaaaaaaaa)
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@haganbmj Good call. It is done.
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@rainbowflash No need to apologize. I'll think about the colours. :)
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@rainbowflash Hmm... So you think it should be less monochromatic?
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So, I redesigned my site the other day. Can any artist bronies offer their opinions from a design perspective? http://www.edwardkim.name
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@extremedash Deter them with yarn.
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@flaxx That sounds fantastic! Have fun.
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@sopada Mhm, it's a very nice style. Although I think my favourite pony-mane-style is actually Octavia's.
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@sopada Fluttershy is my favourite, too. But having said that, Rainbow Dash does have all those pretty colours going for her.
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@darklycute My pins came in the mail today! I immediately put them on my school/work bag. Thanks again! :) http://ur1.ca/4d4d9
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Won a poker game with my friends. 2 hour game with 5 people for a total of $7 in winnings. Student poker is hilarious.
Sunday, 05-Jun-11 02:57:46 UTC from web -
Mmmmm, napping while listening to the rain. Hooray for thunderstorms!
Saturday, 04-Jun-11 15:13:24 UTC from web -
Heading out to take a look at my new house. Hooray for cheap student housing!
Friday, 03-Jun-11 21:28:23 UTC from web -
@bigponymac That's pretty rad. I like it!
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For science, I have spent the last hour of my life creating this. http://ur1.ca/4bz5l
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@edman Actually, I should correct myself: If you only want the acceleration in g forces, then it's actually quite trivial, since you would ignore the acceleration due to gravity.
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@starlightbolt I don't know if it's a two-step process. I would use a = v^2/r for the centripetal acceleration. To calculate the overall acceleration at any point is somewhat involved, because the portion of gravity that contributes to the centripetal acceleration is varying as a function of theta (or as a function of time, if you prefer). However, it's not too difficult to calculate the maximum g-forces experienced (at the bottom of the arc). As it turns out, I'm actually making an infographic about this right now.
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I just saw this: http://1.bp.blogspot.com/-uG3_RgX9JA0/TboU21S9gNI/AAAAAAAAD5w/zkR3VV91S8Y/s1600/6733226c0117931aa6df7c8d3a8e7127.jpg While it's a commendable effort, the physics is brutally wrong in it. Would it be pretentious to try to correct it?
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@elementalparadise I spent my first year in Guelph's party res. It was... an interesting experience, to say the least. I'm planning to spend the rest of my undergrad in a quieter atmosphere. Gotta get those grades and whatnot.
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@elementalparadise uToronto, eh? Haha, yeah, it's pretty notorious for being academically focussed. I have quite a few friends there studying sciences.
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@scribus Mhm. You can't see it in the photo, but Pinkie Pie's tail is also done really well.
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@pinkiederp Toys R Us.
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@starshine Blame Hasbro. But whatever, once more accurate models come out, I'll buy those too.
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Best day ever! http://ur1.ca/4bwx2
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@starshine Van Gogh?
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@stockingsparkle Welcome! I'm sure you'll find that RDN is the friendliest of friendly places! (and the most humble)
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Okay, this is officially the coolest logo I've seen in a while: http://www.equestriachronicles.com/
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All that math this morning has gotten me worked up, so I imagined this fun scenario: Rainbow Dash has fallen prey to one of Pinkie Pie's diabolical pranks! Due to a paint-related mishap, her light-blue coat is now dyed green (lambda_1 = 510 nm). Not wanting to be seen in this state by you, the diligent stationary observer, she races in a straight line towards you, in an attempt to blue-shift her coat back to its original light-blue colour (lambda_2 = 480 nm). How fast must she fly in order to have you perceive her coat as its original colour? Assume Doppler shifting in flat spacetime. (For reference, the answer that I worked out is 1.8 x 10^7 m/s - much faster than the required speed for a Sonic Rainboom!).
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@carcinopony Also, if you're interested, we can add more to this to make it cooler and more useful/applicable. Now that you've figured out how to calculate your wealth from having a part time job, what if you want to spend money too? How much is safe to spend? Let's say that by the end of two months (your summer vacation), you want to have saved $1400. How much can you spend per week during those two months, and come out with exactly $1400? We already know from the previous part that for your wealth, y = 200x + 500. For two months, x=8. So, y = 200*8 +500, which gives y = $2100. $2100 - $1400 = $700. In other words, you can afford to spend $700 throughout your two months of summer vacation. How much is that per week? $700/8 = $87.50. Therefore, using only linear equations and basic math, you've budgeted for $87.50 per week. Hooray!
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@carcinopony I'm sorry. I think I may have gone overboard using function notation - I think that's introduced in Grade 11 in most North American schoolboards. Let me try again: You're probably used to seeing linear equations in the "y = mx + b" form. "m" is your slope, or rate of change. In the finance example, the "rate of change" at which your wealth changes is simply your payrate, or $200 per week. The "b," is the y-intercept, or you can also think of it as an "initial value." Since you start with $500 saved, then b = 500. Thus, to determine your wealth in that example, the linear equation should be y = 200x + 500. Is that explanation clearer?
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@foxox This is true. I remember I started really learning the applications of this stuff when we did raycasting in CS class in high school. Funny story about that - In English class, we read that Victorian era people believed that light was cast from one's eyes, instead of reflected off of surfaces. i.e., Victorians believed in raycasting.
